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Prove: For all sets AB, and CIA-B) U (A n B) = A

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  1. 19 April, 06:28
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    Step-by-step explanation:

    (A-B) U (A∩B) [ We know that difference of A and B is A∩B')

    A∩B') U (A∩B)

    A∩ (B'UB) (Using Distributive law)

    A∩ (U) [ Union of a set and its complement is always a universal set]

    A Hence proved
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