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30 December, 02:26

2a (5-b) = 3b+7 solve for b

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  1. 30 December, 02:56
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    2a (5-b) = 3b+7

    [open bracket]

    10a - 2ab = 3b + 7

    [solve for b, so we need to move all terms with b to the left]

    [-3b on both sides]

    10a - 2ab - 3b = 3b + 7 - 3b

    10a - 2ab - 3b = 7

    [move all those without b to the right]

    [-10a on both side]

    10a - 2ab - 3b - 10a = 7 - 10a

    -2ab - 3b = 7 - 10a

    [divide by - 1 through to change b to be positive]

    2ab + 3b = 10a - 7

    [take b out as the common factor]

    b (2a + 3) = 10a - 7

    [divide by (2a+3) through]

    b = (10a - 7) / (2a+3)
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