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Gracelyn Silva
Mathematics
30 December, 02:26
2a (5-b) = 3b+7 solve for b
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Yuliana Jackson
30 December, 02:56
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2a (5-b) = 3b+7
[open bracket]
10a - 2ab = 3b + 7
[solve for b, so we need to move all terms with b to the left]
[-3b on both sides]
10a - 2ab - 3b = 3b + 7 - 3b
10a - 2ab - 3b = 7
[move all those without b to the right]
[-10a on both side]
10a - 2ab - 3b - 10a = 7 - 10a
-2ab - 3b = 7 - 10a
[divide by - 1 through to change b to be positive]
2ab + 3b = 10a - 7
[take b out as the common factor]
b (2a + 3) = 10a - 7
[divide by (2a+3) through]
b = (10a - 7) / (2a+3)
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