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9 August, 05:52

A ball is shot straight up into the air from the ground with initial velocity of 45ft/sec. Assuming that the air resistance can be ignored, how high does it go?

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  1. 9 August, 06:20
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    V2^2 = V1^2 - 2gh

    => 0 = 44^2 - 2 (32.2) h

    => h = 44^2 / 64.4 = 30.062 ft
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