Mathematics

11 April, 08:41

Given

/qquad m / angle AOCm∠AOCm, angle, A, O, C is a straight angle.

/qquad m / angle BOC = 6x + 29^/circm∠BOC=6x+29

∘

m, angle, B, O, C, equals, 6, x, plus, 29, degrees

/qquad m / angle AOB = 3x + 124^/circm∠AOB=3x+124

∘

m, angle, A, O, B, equals, 3, x, plus, 124, degrees

Find m/angle BOCm∠BOCm, angle, B, O, C:

+3

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