A trapeziodal pyramid has a volume 2856insquared the height of the pyramid is 24in and the lengths of the 2 two bases of the trapeziodal base are 13 and 29 in what is the height of the trapeziodal base

V = 1/3Bh

B = 1/2 (b1 + b2) t

V = 1/3[1/2 (b1 + b2) t] * h

h = 24

b1 = 13

b2 = 29

t = ?

V = 2856

Substitute:

2856 = 1/3[1/2 (13 + 29) t] (24)

2856 = 1/6 (42) (24) t

2856 = 7 (24) t

2856 = 168t

t = 2856/168 = 17 in height of the trapeziod