Ask Question
26 December, 20:54

Two bags both contain blue marbles and green marbles. Bag A contains 6 blue marbles and 4 green marbles and Bag B contains 2 blue marbles and 3 green marbles. A marble is drawn from each bag. What is the probability that both marbles are green?

+2
Answers (1)
  1. 26 December, 21:09
    0
    6/25

    Step-by-step explanation:

    Total marbles in Bag A = 6 blue + 4 green = 10 marbles.

    Total marbles in Bag B = 2 blue + 3 green = 5 marbles.

    P (Green marble is drawn from Bag A) = Green Marbles/Total Marbles = 4/10.

    P (Green marble is drawn from Bag B) = Green Marbles/Total Marbles = 3/5.

    Assuming that both the above probabilities are independent, therefore:

    P (Both marbles are green) = 4/10 * 3/5 = 12/50 = 6/25.

    Hence, the probability is 6/25!
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Two bags both contain blue marbles and green marbles. Bag A contains 6 blue marbles and 4 green marbles and Bag B contains 2 blue marbles ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers