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1 November, 02:35

Use the transformations on the function f (x) = x| to select the correct graph of f (x) = 1/3lxl+1

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  1. 1 November, 03:04
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    The graph would be compressed and shifted up 1.

    A number in front of the absolute value will either stretch or shrink the graph; since 0 < 1/3 < 1, this is a shrink.

    A number added after the absolute value will either move the graph up or down the number of units added. Since it was a positive number added, it will move the graph up.
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