Ask Question
25 December, 07:35

Write an equation of the line through (3,-5) and perpendicular to 3y=x-6

+4
Answers (1)
  1. 25 December, 07:41
    0
    3y = x - 6

    y = 1/3x - 2.

    slope her is 1/3. A perpendicular line will have anegative reciprocal slope. To find the negative reciprocal of a number, u flip the number and change the sign. So the slope we need os - 3/1 or just - 3. (see how I flipped the slope and changed the sign)

    y = mx + b

    slope (m) = - 3

    (3,-5) ... x = 3 and y = - 5

    now we sub and find b, the y int

    -5 = - 3 (3) + b

    -5 = - 9 + b

    -5 + 9 = b

    4 = b

    so ur perpendicular equation is : y = - 3x + 4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Write an equation of the line through (3,-5) and perpendicular to 3y=x-6 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers