The vertex form of the equation of a parabola is y = (x+3) ^2+53. what is the standard form?

y = x² + 6x + 62 ~apex I did it and it is correct

"Standard form" appears like y = ax^2 + bx + c.

Starting with y = (x+3) ^2+53, perform the indicated exponentiation / multiplication:

y = x^2 + 6x + 9 + 53.

Combining the constants, we get

y = x^2 + 6x + 62, which is the equation of a parabola in standard form.