3[2 (x-3) + 2]+5 (x-3)

algebra2

11x-27 is the answer

Perform what's inside the brackets first

"2 (x-3) + 2" - - - > 2x-6+2 - - - > simplify (add the 2 and the - 6 together) - - - > 2x-4 - - - > put your simplified version back into the brackets - - - > [2x-4]

Now multiply your 3 with whatever is in the brackets to get rid of the brackets

"3[2x-4]"

6x-12

Do the same with the 5 and whatever is still in parenthesis after the 5

"5 (x-3) "

5x-15

Add the two simplified terms together

"6x-12+5x-15"

combine the like terms - - - > 6x+5x=11x and - 12 (+) - 15=-27

Put your two answers back into one equation

"11x-27"

And that is your final answer