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Jenny Bowen
Mathematics
14 March, 03:21
Simplify, if possible.
log2 (0.5) 4
+2
Answers (
1
)
Fernando Fleming
14 March, 03:50
0
Case 1
let A=log2 (0.5) 4 = log (0.5) 4 x log (0.5) 4 = 4log (0.5) x 4log (0.5) = 16 log (0.5 + 0.5) = 16 log 1 = 0 if it is a neperian logarithm
case 2
logn n = 1, if it is logarithm with n as a basis,
so A=log2 (0.5) 4 = 4log2 (0.5) = - 4 log2 (2) = - 4 x1 = - 4
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