What are the roots of the equation x^2+6x-9=10?

-3+2sqrt7

-3-2sqrt7

Step-by-step explanation:

x^2+6x-9=10

x^2+6x-9-10=0

x^2+6x-19=0

ax^2+bx+c=0

a=1 b=6 c=-19

As cannot be solved by completing square we will use quadratic equation

x = (-b+sqrt (b^2-4ac)) / 2a and x = (-b-sqrt (b^2-4ac)) / 2a

x = (-6+sqrt (6^2-4*-19)) / 2 and x = (-6-sqrt (6^2-4*-19)) / 2

x = (-6+sqrt (36+76)) / 2 and x = (-6-sqrt (36+76)) / 2

x = (-6+4sqrt7) / 2 and x = (-6-4sqrt7) / 2

x = (-3+2sqrt7) and x = (-3-2sqrt7)

x=2.29 and x = - 8.29