Find 1/3u, if u = (1, - 3)

(1, - 1)

(1/3, - 1)

(3, - 9)

(1, - 9)

For this case we have the following vector:

u = (1, - 3)

When multiplying by the scalar 1/3 we have:

1 / 3u = (1/3) (1, - 3)

Rewriting the new vector we have:

1 / 3u = (1/3, - 3/3)

1 / 3u = (1/3, - 1)

Answer:

1 / 3u = (1/3, - 1)