Recall that 0°C = 32°F and 100°C = 212°F

•Using x for degrees Celsius and y for degrees Fahrenheit, find an equation of the line passing through (0,32) and (100,212).

•What is the slope of the line? Explain what the y-intercept means in terms of degrees Celsius and degrees Fahrenheit.

•What is the y-intercept of the line? Explain what the y-intercept means in terms of degrees Celsius and degrees Fahrenheit.

(0,32) (100,212)

slope = (y2 - y1) / (x2 - x1)

slope (m) = (212 - 32) / (100 - 0) = 180/100 = 9/5 (or 1.8)

so the slope of the line is 9/5 ... this means that a farenheit degree change is equivalent to a celsius change of 9/5 (or 1.8 degrees)

now we find the y int.

y = mx + b

slope (m) = 9/5

(0,32) ... x = 0 and y = 32

now we sub and find b, the y int

32 = 9/5 (0) + b

32 = b

so ur y int is 32 ... this means that when celsius temp starts at 0, farenheit temp is 32 degrees