2x^{2} + 4x+1=0

Solve for x.

2x^2 + 4x + 1 = 0

2x^2 + 4x + 1 - 1 = 0 - 1

2x^2 + 4x = - 1

X (2x + 4) = - 1

X = - 1.

2x + 4 = - 1

2x + 4 - 4 = - 1 - 4

2x = - 5

2x/2 = - 5/2

X = - 5/2.

I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.