A researcher wanted to know if the content of television programs has an impact on viewer's recall of ad content. He randomly assigned 108 people to view a program with violent content, and 110 people to view a program with neutral content. The same 9 commercials were inserted into each program. After viewing the program, the subjects were asked to recall the brands advertised in the commercials. The average number of brands recalled for those who saw the violent program was 3.77 with standard deviation 1.87. The average number of brands recalled for those who saw the neutral program was 4.65 with standard deviation 1.67. The standard error for A researcher wanted to know if the content of tele is

A. 0.180

B. 0.058

C. 0.240

Question

Yesenia Wallace

Mathematics

4 March, 02:38

A researcher wanted to know if the content of television programs has an impact on viewer's recall of ad content. He randomly assigned 108 people to view a program with violent content, and 110 people to view a program with neutral content. The same 9 commercials were inserted into each program. After viewing the program, the subjects were asked to recall the brands advertised in the commercials. The average number of brands recalled for those who saw the violent program was 3.77 with standard deviation 1.87. The average number of brands recalled for those who saw the neutral program was 4.65 with standard deviation 1.67. The standard error for A researcher wanted to know if the content of tele is

A. 0.180

B. 0.058

C. 0.240

+2

Answers (1)

Know the Answer?

Diya Ross · Answer 1

A. 0.180

Step-by-step explanation:

The standard error for A researcher wanted to know if the content of tele

researcher A is

N = He randomly assigned 108 people to view a program with violent content,

The average number of brands recalled for those who saw the violent program was 3.77 with standard deviation 1.87

The standard deviation of a sampling distribution of mean values is called the standard error of the means, thus standard error of the means,

σx = σ / √N

When sampling is done with replacement, the total number of possible samples (two or more can be the same) is inﬁnite.

therefore,

σx = σ / √N

σx = 1.87 / square root of 108

σx = 1.87 / 10.4 = 0.1798 = ±0.18

The standard error for program with violent content is ±0.18