Find the area of a 45°-45°-90° triangle with a hypotenuse of 24. a. 144 square units c. 99 square units b. 125 square units d. 100 square units

Area=1/2 times base times height

remember that 45-45-90 triangle has sides of x, x and x√2

(legs are measure x and hypotonuse=x√2)

the legs are equal and are also the base and height

find the legs (x=leg)

hypotonuse=24

24=x√2

divide both sides by √2

24 / (√2) = leg=base=height

volume=1/2 times base times heigth

V=1/2 times (24/√2) times (24/√2)

V=1/2 times (576/2)

V=576/4

V=144 units^2

answer is A