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6 June, 07:05

For what value (s) of p will the equation x^2=p have 2 real number solutions? Explain your reasoning?

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  1. 6 June, 07:28
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    p > 0

    Step-by-step explanation:

    x² = p

    x² - p = 0

    A = 1, B = 0, C = - p

    For 2 real roots:

    B² - 4AC > 0

    0² - 4 (1) (-p) > 0

    4p > 0

    p > 0
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