Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts

jumping. Here, t is entered in radians.

H (t) = -0.6 cos (2pi/2.5) t + 1.5

What is the second time when Luiza reaches a height of 1.2 m?

Round your final answer to the nearest hundredth of a second.

Question

Messiah Young

Mathematics

6 August, 04:07

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts

jumping. Here, t is entered in radians.

H (t) = -0.6 cos (2pi/2.5) t + 1.5

What is the second time when Luiza reaches a height of 1.2 m?

Round your final answer to the nearest hundredth of a second.

+4

Answers (1)

Know the Answer?

Sampson · Answer 1

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H (t) = -0.6cos (2pi/2.5) t+1.5 should be equal to 1.2. If calculated, - 0.6cos (0.8pi) t=1.2-1.5 which is equal to - 0.6cos (0.8pi) t=-0.3, then cos (0.8pi) t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos (0.8pi) t=cos (pi/3). If simplified, (0.8pi) * t=5pi/3. pi's are cancelled out and t is calculated as 2.08333 ... If rounded to the nearest hundredth it is 2.08.