Ask Question
24 August, 09:57

probability that cars have been assembled in a particular plant as follows: P (plant1) = 20%, P (plant 2) = 24%, P (plant 3.25%, P (plant 4) = 31% Total number of cars manufactured by all plants: 1.2 million/year Number of cars of no warranty claims manufactured by plant1: 223200/year Compute the warranty claim rate of the cars assembled in plant 1

+4
Answers (1)
  1. 24 August, 10:20
    0
    16800/year

    Step-by-step explanation:

    Plant 1 = 20%

    Plant 2 = 24%

    Plant 3 = 25%

    Plant 4 = 31%

    Total cars produced 100% = 1,200,000

    Number of cars produced in plant 1 =

    20% of 1,200,000 = 0.2 x 1,200,000 = 240,000 cars

    Number of cars produced in plant 2 =

    24% of 1,200,000 = 0.24 x 1,200,000 = 288,000 cars

    Number of cars produced in plant 3 =

    25% of 1,200,000 = 0.25 x 1,200,000 = 300,000 cars

    Number of cars produced in plant 4 =

    31% of 1,200,000 = 0.31 x 1,200,000 = 372,000 cars

    Number of cars with no warranty claim in plant 1/year 223200

    Number of cars with warranty claims in plant 1 + number of cars with no warranty claim in plant 1 = total number of cars produced in plant 1

    X + 223200 = 240000

    X = 240000 - 223200

    X = 16800/year

    number of cars with warranty claim in plant 1 / year is 16800
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “probability that cars have been assembled in a particular plant as follows: P (plant1) = 20%, P (plant 2) = 24%, P (plant 3.25%, P (plant ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers