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Ryker David
Mathematics
6 May, 18:46
For what value of n is n + 1p3 = np4
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Carl Kaiser
6 May, 19:04
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(n + 1) P 3 = (n + 1) (n) (n - 1)
n P 4 = n (n - 1) (n - 2) (n - 3) so make those equal. Both have n and (n - 1) so divide by those to cancel them out leaving
n + 1 = (n - 2) (n - 3)
n + 1 = n^2 - 5n + 6
0 = n^2 - 6n + 5
0 = (n - 1) (n - 5)
so n either = 1 or = 5. But it can't be 1 since the number before P has to be ≥ the number after.
So the only answer is n = 5
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