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25 September, 10:44

Jane deposited $10,000 into her bank account in December, 2010. Her account earns interest at a rate of 5% compounded monthly. How much money will she have in December of this year (2018) ?

Round your answer to the nearest whole number.

Compound Interest: A = P (1 + r/n) ^nt

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Answers (2)
  1. 25 September, 10:48
    0
    14905.85

    Step-by-step explanation:

    P (1+r/n) ^nt

    10000 (1 + (.05/12)) ^ (12*8)
  2. 25 September, 11:03
    0
    she will have $14,906 in December of year 2018

    Step-by-step explanation:

    To find the amount of money she will have in December of the year 2018, we will simply use the formula;

    Compound Interest: A = P (1 + r/n) ^nt

    where p = principal

    R = rate

    n = the number of times the interest is compounded per unit time

    T = time

    A = Accrued amount

    From the question

    Principal (p) = $10,000

    Rate (r) = 5% = 0.05

    Time (t) = 2018-2010 = 8 years

    n = 12

    We can now proceed to insert the values into our formula;

    Compound Interest: A = P (1 + r/n) ^nt

    = $10 000 (1 + 0.05/12) ^12*8

    =$10,000 (1 + 0.00416667) ^96

    = $10 000 (1.00416667) ^96

    =$10 000 (1.4905859)

    =$14,905.895

    ≈$14,906 to the nearest whole number.

    Therefore she will have $14,906 in December of year 2018
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