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28 December, 03:38

What is the length of a rectangle with an area of 48 yd^2 and a width of 3 yd?

A. 8 yd.

B 16 yd

C 18 yd

D 21 yd

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Answers (2)
  1. 28 December, 03:43
    0
    =12yd

    Step-by-step explanation:

    The area of a rectangle is given by area=length*width

    Therefore, length of a rectangle is obtained by dividing it's area with the width of the rectangle

    Length=Area/Width

    substituting for the values in the formula we get the following

    = 48yd²/3yd

    =12yd
  2. 28 December, 04:00
    0
    Choice B is correct answer.

    Step-by-step explanation:

    From question statement, we observe that

    We have given the width and the area of rectangle.

    Area = 48 yd² and Width = 3 yd

    We use the formula of area of rectangle.

    Area = length * width

    Putting the values of area and width of formula, we get

    48 = length * 3

    Hence, length = 48 / 3

    length = 16 yd

    hence, the length of rectangle is 16 yd.
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