What are the solutions to the equation √x2+2x-10=√x+20

A. x = - 6, x = - 5

B. x = - 6, x = 5

C. x = - 5, x = 6

D. x = 5, x = 6

Answer Is B

√x^2+2x-10=√x+20

raising both members to the square

x^2+2x-10=x+20

rewriting

x^2+x-30=0

factoring

(x+6) (x-5) = 0

therefore the solutions are

x = - 6, x = 5

the answer is

B. x = - 6, x = 5