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12 August, 03:44

3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61

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  1. 12 August, 04:03
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    Let the smallest number be = x

    So the next big number = x+2

    And the largest number = x+4

    x + 4 (x+4) = 61

    x + 4x + 16 = 61

    5x + 16 = 61

    5x = 61-16 = 45

    So x = 45/5 = 9

    Therefore, the numbers are 9, 11 and 13. Answer.

    gsm
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