If f (4) = 246.4 when r = 0.04 for the function f (t) = Pe^rt, then what is the approximate value of P?

Question

Janelle Sanchez

Mathematics

28 March, 04:47

If f (4) = 246.4 when r = 0.04 for the function f (t) = Pe^rt, then what is the approximate value of P?

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Mike Lamb · Answer 1

If f (4) = 246.4 when r = 0.04 for the function f (t) = Pe^rt, then what is the approximate value of P?

Solution:

f (t) = Pe^rt

when r=0.04, the f (t) = 246.4, thus the value of P will be:

246.4=Pe^0.04t

P = (246.4) / (0.04t)

where t=time