Find the distance between (43,-15) & (29,-3)

Question

Saige Zimmerman

Mathematics

8 February, 04:05

Find the distance between (43,-15) & (29,-3)

+2

Answers (2)

Know the Answer?

Raegan Ballard · Answer 1

D^2 = (x2 - x1) ^2 + (y2 - y1) ^2

(x, y)

(43,-15) & (29,-3)

x1 = 43, y1 = - 15

x2 = 29, y2 = - 3

d^2 = (29-43) ^2 + (-3--15) ^2

d^2 = (-14) ^2 + (12) ^2

d^2 = 196 + 144

d^2 = 340

d = sqrt (340)

d = 2*sqrt (85)

d = 18.44

Anya Pruitt · Answer 2

Distance = Square Root ((X difference) ^2 + (Y difference) ^ 2)

Distance = Square Root [ (43 - 29) ^2 + (-15 - - 3) ^2]

Distance = Square Root (14^2 + - 12^2)

Distance = Square Root (340)

Distance = 18.4390889146