Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

All integers where n ≥ 1

All integers where > 1

All integers where n ≥ 4

All real numbers

For this its always greater than one right? for every type of these things?

also Given the arithmetic sequence an = 4 - 3 (n - 1), what is the domain for n?

All integers where n ≥ 1

All integers where n > 1

All integers where n ≤ 4

All integers where n ≥ 4

Question

Aryanna

Mathematics

29 October, 06:55

Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

All integers where n ≥ 1

All integers where > 1

All integers where n ≥ 4

All real numbers

For this its always greater than one right? for every type of these things?

also Given the arithmetic sequence an = 4 - 3 (n - 1), what is the domain for n?

All integers where n ≥ 1

All integers where n > 1

All integers where n ≤ 4

All integers where n ≥ 4

+3

Answers (1)

Know the Answer?

Gabriel Wilcox · Answer 1

Since r is greater than 1, that means integers greater than or equal to 1.

It can't be all real numbers, because that would include negative number.

If the starting number of a sequence is 4, if we put n=0, then we get 4, but if we put in a negative n, we would get a value that isn't part of our sequence, so it has to be n is greater than or equal to 1.