I=/sqrt{-1}i = - 1 i, equals, square root of, minus, 1, end square root, what is the sum (7+3i) + (-8+9i) (7+3i) + (-8+9i) left parenthesis, 7, plus, 3, i, right parenthesis, plus, left parenthesis, minus, 8, plus, 9, i, right parenthesis?

Question

Jakob Holland

Mathematics

30 June, 08:36

I=/sqrt{-1}i = - 1 i, equals, square root of, minus, 1, end square root, what is the sum (7+3i) + (-8+9i) (7+3i) + (-8+9i) left parenthesis, 7, plus, 3, i, right parenthesis, plus, left parenthesis, minus, 8, plus, 9, i, right parenthesis?

+1

Answers (1)

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Edith · Answer 1

We can simply add the expression to simplify the expression. So,

(7+3i) + (-8+9i) = 7 + 3i - 8+9i Get rid of paranthesis.

= (7-8) + (3i+9i) Group the like terms.

= - 1 + 12i