What is the standard form of this function?

F (x) = - (x-4) ^2 + 2

f (x) = - 2 (x + 6) ^2 + 2

Step-by-step explanation:

f (x) = - 2x^2 - 24x - 70 <-- - divide out - 2 out of the first two terms ...

f (x) = - 2 (x^2 + 12x) - 70 <- - divide the x coefficient by 2 and then square it, then add AND subtract it)

f (x) = - 2 (x^2 + 12x + (12/2) ^2 - (12/2) ^2) - 70

f (x) = - 2 (x^2 + 12x + 36 - 36) - 70 <-- - distribute the - 2 onto - 36 to get it out of the brackets ...

f (x) = - 2 (x^2 + 12x + 36) + 72 - 70 <- - combine constants and factor perfect square trinomial ...

f (x) = - 2 (x + 6) ^2 + 2 <- - standard form ...

Answer: f (x) = - x^2 + 8x - 14

Step-by-step explanation:

just took the test.