If the quadratic formula is used to find the solution set of 3 x^2 + 4 x - 2 = 0, what are the solutions?

3 x^2 + 4 x - 2 = 0

a = 3

b = 4

c = - 2

x = [-b + - sq root (b^2 - 4ac) / 2a

x = [-4 + - sq root (16 - 4*3*-2) ] / 2*3

x = [-4 + - sq root (16 + 24) ] / 6

x1 = - (2 / 3) + sq root (40) / 6

x1 = - (2 / 3) + 6.3245553203 / 6

x2 = - (2 / 3) - 6.3245553203 / 6