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8 September, 11:11

What are the zeros of the function f (x) = 2x^2+16x-9

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  1. 8 September, 11:12
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    So the step process for this is to factor it out so this is a complex trinomial so u will have to multiply 2 by - 9 and the rest should be in your notes.

    then once u factor it out you rearrange those two factored brackets and example of this would be

    (x+3) (2x+1)

    so x+3=0

    therefore x=-3. you bring the 3 over to where the zero is and change the sign

    for 2x+1=0

    2x=-1

    2x/2=-1

    x=-1/2

    so for this one you isolate for x and in order to get rid of 2x you divide by 2 for both
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