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3 December, 08:40

How many 6 digit odd numbers are possible if the leftmost digit cannot be zero?

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  1. 3 December, 08:57
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    The correct answer is 9 x 5 x 10 = 450
  2. 3 December, 09:05
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    There are 9 choices for the first digit: 1,2,3,4,5,6,7,8,9

    There are 10 choices for the second digit: 0,1,2,3,4,5,6,7,8,9

    There are 5 choices for the third digit: 1,3,5,7,9

    That's 9*10*5 = 450
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