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6 August, 21:26

The formula for the area of a triangle is a=1/2bh. Hiro is solving the equation for h; his work is shown below. What mistake did Hiro make?

a=1/2bh

2 (x) a=2 (x) (1/2bh)

2a=bh

2a-b=h

(x) is multiplication sign btw

Hiro should have divided both sides of the equation by 2. Hiro should have divided both sides of the equation by b. Hiro should have added b to both sides of the equation. Hiro should have subtracted 2 from both sides of the equation.

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Answers (2)
  1. 6 August, 21:30
    0
    Hiro should divide both sides by 2.
  2. 6 August, 21:30
    0
    Hiro should have divided both sides of the equation by 2.

    Example

    If b = 5 and h = 10

    a = 1/2 * b * h

    a = 1/2 * 5 * 10

    a = 25

    2a = 2 (1/2 * b * h)

    2 * 25 = 2 (1/2 * 5 * 10)

    50 = 2 (25)

    50 = 50

    2a = b * h

    2 * 25 = 5 * 10

    50 = 50

    2a - b = h

    2 * 25 - 5 = 10

    50 - 5 = 12

    45 = 10

    This is false.

    If Hiro divided both sides by 2 instead:

    2a : 2 = b * h : 2

    2 * 25 : 2 = 5 * 10 : 2

    50 : 2 = 50 : 2

    25 = 25
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