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6 July, 14:42

Let f (x) = 2x+2. solve f^-1 (x) when x=4

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  1. 6 July, 14:54
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    F⁻¹ (x) is the notation for the inverse of an equation, so you just need to find the inverse equation. that's found by swapping your x and y variables:

    f (x) = 2x + 2 ... replace f (x) with y

    y = 2x + 2 ... swap x and y variables

    x = 2y + 2 ... solve for y

    x = 2y + 2 ... subtract 2

    x - 2 = 2y ... divide by 2

    (x - 2) / 2 = y

    so, f⁻¹ (x) = (x - 2) / 2 ... now you need to solve that for when x = 4. plug it in:

    f⁻¹ (x) = (4 - 2) / 2 ... simplify the top of the fraction

    f⁻¹ (x) = 2/2

    f⁻¹ (x) = 1 is your answer.
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