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16 October, 18:43

Which of the following are the solutions of the equation 2x^2+2x=4-x

(A) x=4 and x=1

(B) x=4 and x = - 1/2

(C) x = 3+√35/4 and x=3-√35/4

(D) x=-3+√41/4 and - 3-√41/4

(E) - 3+i√23/2 and - 3-i√23/2

+1
Answers (1)
  1. 16 October, 18:56
    0
    2x² + 2x = 4 - x

    + x + x

    2x² + 3x = 4

    2x² + 3x - 4 = 0

    x = - (3) + / - √ ((3) ² - 4 (2) (-4))

    2 (2)

    x = - 3 + / - √ (9 + 32)

    4

    x = - 3 + / - √ (41)

    4

    x = - 3 + / - 6.4

    4

    x = - 0.75 + 1.6

    x = - 0.75 + 1.6 x = - 0.75 - 1.6

    x = 0.85 x = - 16.75

    The answer is equal to D. x = - 0.75 + √ (41) / 4 and x = - 0.75 - √ (41) / 4.
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