A tennis ball can in the shape of a right circular cylinder holds three tennis balls snugly. If the radius of a tennis ball is 3.3 cm, what percentage of the can is not occupied by tennis balls?

Step-by-step explanation:

1. - Volumeo f the circular cylinder (to holds three balls)

each ball is 3,3 cm radius then is 6,6 cm diameter

Then 3 diameters are equal to 3 * 6.6 = 19,8 cm (the height of the cylinder)

Then the volume of the cylinder is

V (c) = π*r²*h ⇒ V (c) = 3,14 * (3,3) ²*19,8 ⇒ V (c) = 677.05 cm³

Now the volume of a tennis ball (is an sphere)

V (s) = 4/3*π*r³ ⇒ V (s) = 4/3*3,14 * (3,3) ³ ⇒ V (s) = 150,46 cm³

We have three balls then volume of the three balls

150,46*3 = 451.37 cm³

So V (c) = 677,05 cm³ V (bt) = 451,41

V (c) / V (bt) = 677,05 / 451,41 = 1,498

Then V (c) is 49.8 % bigger than of V (bt) of three balls