N^2=-35-12n

How answer this question

n² = - 35 - 12n

Add 12n and 35 to both sides

n² + 12n + 35 = 0

Find the factors of 35 that add or subtract to positive 12:

Factors of 35: 1, 5, 7, 35

5 and 7 add up to 12

n² + 12n + 35 = 0

Instead of 12n, you can replace it with 7n + 5n because they add up to 12n

n² + 7n + 5n + 35

Factor the equation separately

n (n + 7) + 5 (n + 7)

Now factor out the (n + 7)

(n + 7) (n + 5)