Solve each system by substitution:

3x+y=2

4x+y=20

How do I solve this and set this up

Solve the first equation for y.

3x+y=2

y=2-3x

Substitute

4x + (2-3x) = 20

4x+2-3x=20

x=18

So you want to isolate one of the variables in one of the equations. Using the first equation, we can make 3x+y=2 y=2-3x.

Then plug y=2-3x into the second equation:

4x + (2-3x) = 20

Then solve.

x+2=20

x=18

Finally, plug the x value back into any of the two equations to find y. This is essential to get full credit!

4 (18) + y=20

72+y=20

y = - 52

x=18

y = - 52