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5 June, 02:26

Solve the quadratic equation x^2+2x-8=0 by factoring

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Answers (2)
  1. 5 June, 02:41
    0
    The solutions for the equation are:

    x = 2

    x = - 4
  2. 5 June, 02:45
    0
    x = - 4, x = 2

    Step-by-step explanation:

    Given

    x² + 2x - 8 = 0

    Consider the factors of the constant term ( - 8) which sum to give the coefficient of the x - term ( + 2)

    The factors are + 4 and - 2, since

    4 * - 2 = - 8 and 4 - 2 = + 2, hence

    (x + 4) x - 2) = 0 ← in factored form

    Equate each factor to zero and solve for x

    x + 4 = 0 ⇒ x = - 4

    x - 2 = 0 ⇒ x = 2
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