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29 November, 01:29

Find the equation that is equivalent to the quadratic equation shown. Explain why

x² - 6x - 27 = 0

A.) x (x - 3) = 27

B.) (x - 6) ² = 63

C.) (x - 3) ² = 36

D.) (x - 3) ² = 28

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Answers (1)
  1. 29 November, 01:31
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    C - (x-3) ^2=36

    If we expand (x-3) ^2=36:

    (x-3) (x-3) = 36

    x^2-3x-3x+9=36

    x^2-6x+9=36

    Then subtract 36

    x^2-6x-27=0
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