Solve the system.

3x+2y=-2 6x-Y=-6

So we assume that x=x and y=y is true for both situations so

3x+2y=-2

6x-y=6

6x-y=6

add y to both sides

6x=6+y

subtract 6 from both sides

6x-6=y

subsitute (6x-6) for y in first equation

3x+2 (6x-6) = - 2

distribute

3x+12x-12=-2

add like terms

15x-12=-2

add 12 to both sides

15x=10

divide both sides by 15

x=2/3

subsitute

3x+2y=-2

3 (2/3) + 2y=-2

6/3+2y=-2

2+2y=-2

subtract 2 from both sides

2y=-4

divide both sides by 2

y=-2

x=2/3

y=-2

solution in (x, y) form

(2/3,-2)