Two consecutive integers are such that 3 times the larger exceeds twice the smaller by 34. find the integers.

Answer: larger = 32 and smaller = 31

Step-by-step explanation:

let's call the smaller x. The larger must be x+1, because they are consecutives.

3 times the larger exceeds twice the smaller by 34, so:

3 (x+1) = 2x+34

3x+3=2x+34

3x-2x=34-3

x=31

x+1 = 32

Checking:

3.32 = 92

3.31+34 = 96 ok

x - a smaller number

(x+1) - a larger number

3 (x+1) - 2x = 34

3x + 3 - 2x = 34

x = 31

(x+1) = 32