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25 November, 03:32

Plot the x - and y - intercepts of the function.

f (x) = x3+2x2-x-2

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  1. 25 November, 03:55
    0
    see below for a plot

    Step-by-step explanation:

    The y-intercept is where x=0:

    f (0) = 0^3 + 2·0^2 - 0 - 2 = - 2

    The x-intercepts can be found where f (x) = 0:

    0 = x^3 + 2x^2 - x - 2 = x^2 (x + 2) - 1 (x + 2) = (x^2 - 1) (x + 2)

    0 = (x + 1) (x - 1) (x + 2)

    The values of x that make these factors zero are {-2, - 1, 1}.

    The x-intercepts are (-2, 0), (-1, 0), (1, 0). The y-intercept is (0, - 2).
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