Ask Question
8 July, 13:52

The admission fee at an amusement park is $3.25 for children and $5.80 for adults. On a certain day, 369 people entered the park, and the admission fees collected totaled 1671 dollars. How many children and how many adults were admitted?

+2
Answers (1)
  1. 8 July, 14:19
    0
    185 adults and 184 children

    Step-by-step explanation:

    People entering the park = adults plus children

    369 = a+c

    Total money = admission fee for kids * number of children + admission fee for adults * number of adults

    1671 = 3.25c + 5.80a

    We have 2 equations and 2 unknowns

    Solve the first equation for a by subtracting c from each side

    369-c = a+c-c

    369-c = a

    Substitute this in to the second equation

    1671 = 3.25 c + 5.80 (369-c)

    Distribute the 5.8

    1671 = 3.25c + 5.8*369 - 5.8c

    1671 = 3.25c + 2140.2-5.8c

    Combine like terms

    1671 = - 2.55c + 2140.2

    Subtract 2140.2 from each side

    1671-2140.2 = - 2.55c + 2140.2-2140.2

    -469.2 = - 2.55c

    Divide by - 2.55 on each side

    -469.2/-2.55 = - 2.55c/-2.55

    184 = c

    There were 184 children

    Now we need to find a

    369 = a+c

    369 = a+184

    Subtract 184 from each side

    369-184 = a+184-184

    185 = a

    There were 185 adults
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The admission fee at an amusement park is $3.25 for children and $5.80 for adults. On a certain day, 369 people entered the park, and the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers