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Giancarlo Rojas
Mathematics
26 October, 22:48
Find the x and y intercepts 2x + 3y + 16 = 5y + 4
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Robert Mann
26 October, 22:57
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For the x intercepts, replace y with 0
for y intercepts, replace x with 0
x-int:
2x+3 (0) + 16=5 (0) + 4
2x+16=4
2x=-12
x=-2
y-int:
2 (0) + 3y+16=5y+4
3y+16=5y+4
12=2y
y=6
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