The recursive rule is f (1) = 99; f (n) = f (n-1) + 4 and one of the terms is 119. What position is 119 in for this sequence?

Question

Beckham Foley

Mathematics

20 September, 03:00

The recursive rule is f (1) = 99; f (n) = f (n-1) + 4 and one of the terms is 119. What position is 119 in for this sequence?

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Kirk · Answer 1

F (1) = 99

f (2) = f (1) + 4 = 99 + 4 = 103

nth term of an arithmetic sequence is given by Tn = a + (n - 1) d; where Tn = 119, a = 99 and d = 4

119 = 99 + (n - 1) 4 = 99 + 4n - 4 = 95 + 4n

4n = 119 - 95 = 24

n = 24/4 = 6

Therefore, 119 is in the 6th position.