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Herrera
Mathematics
21 February, 15:09
How do you do 5ln x = 35 ... ?
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Jaylah Jennings
21 February, 15:37
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That's going to depend a lot on what you want to "do" to it.
I'm going to assume that you want to find a number for 'x' that makes
the whole equation a true statement. Here's how I would do it:
5 ln (x) = 35
Divide each side by 5: ln (x) = 35/5
ln (x) = 7
Raise 'e' to the power of each side: e^[ ln (x) ] = e⁷
But e^[ ln (x) ] is just 'x'. So x = e⁷ = 1,096.633 ... (rounded)
That's the only number you can write in place of 'x'
and make the original equation true.
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