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11 June, 19:24

Which expression is equivalent to log8 4a (b-4/c4) ?

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  1. 11 June, 19:54
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    The answer:

    the main rules of the use of logarithm are

    loga[a] = 1

    loga[AxB] = loga[A] + loga[B] for all value positive of A and B

    loga[A/B] = loga[A] - loga[B] for all value positive of A and B

    in our case, log8 4a (b-4/c4)

    so it is equivalent to log8 4a + log8 (b-4/c4)

    and since loga[A/B] = loga[A] l - oga[B], log8 (b-4/c4) = log8 (b-4) - log8 (c4)

    the possible expression:

    log8 4a (b-4/c4) = log8 4a + log8 (b-4) - log8 (c4)
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