Define a random variable x = number of times that owner-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let x = 4 represent 4 or more times. Round your answers to four decimal places.)

The question is incomplete since the data is missing from it. I am writing the complete question below:

The American Housing Survey reported the following data on the number of times that owner-occupied and renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months.

Number of Houses (1000s)

Number of Times Owner Occupied Renter Occupied

0 547 23

1 5,012 541

2 6,110 3,734

3 2,544 8,660

4 times or more 557 3,784

Do not round intermediate calculations. Round your answers to two decimal places.

a. Define a random variable x = number of times that owner-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let x = 4 represent 4 or more times.)

Answer:

x f (x)

0 0.0370

1 0.3393

2 0.4137

3 0.1722

4 0.0378

Total 1

Step-by-step explanation:

Total no. of times owner occupied units had a water supply stoppage lasting 6 or more hours:

547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000

x = no. of times owner occupied units had a water supply stoppage.

P (x=0) = 547000/14770000

P (x=0) = 0.0370

P (x=1) = 5012000/14770000

P (x=1) = 0.3393

P (x=2) = 6110000/14770000

P (x=2) = 0.4137

P (x=3) = 2544000/14770000

P (x=3) = 0.1722

P (x=4) = 557000/14770000

P (x=4) = 0.0378

x f (x)

0 0.0370

1 0.3393

2 0.4137

3 0.1722

4 0.0378

Total 1